Skip to main content

Lowest common ancestor of binary search tree

Question : Write a function to print the lowest common ancestor of two nodes in a binary search tree. 

Lowest common ancestor of two nodes x and y in a binary tree is the lowest node that has both x and y as descendants.


Here lowest common ancestor of 1 and 7 is 3. LCA of 13 and 7 is root - 8. And LCA of 6 and 7 is 6 itself.

The program to find gets complicated for an ordinary binary tree. But for a binary search tree, it is quite simple.


As we see from the diagram above, the paths to 1 and 4 are common till the node 3. And at 3 they branch in different directions. So 3 is our LCA.

That is lowest common ancestor is the node where the paths to x and y from root deviate. As long as they branch in same direction, we continue to traverse. When they branch in different directions, that is the lowest common ancestor.

So let us write a simple algorithm,
  1. set temp=root
  2. if temp->val >x and temp->val>y
    1. temp = temp->left
  3. else if temp->val<x and temp->val <y
    1. temp = temp->right
  4. if neither then  break the loop and we have found our LCA
  5. repeat steps 2 to 6 until temp is null
Here is the function for finding lowest common ancestor in C.



NODEPTR lowest_common_ancestor(NODEPTR root, int num1,int num2)
{
   NODEPTR temp = root;
   while(temp!=NULL)
   {
        if(num1>temp->val && num2>temp->val ) 
              temp = temp->right; 
        else if(num1<temp->val && num2<temp->val)
              temp= temp->left;
        else
              break; 
    }
    return temp;  
}
Here is the driver program
#include<stdio.h>
#include<stdlib.h>
struct node
{
   int val;
   struct node *left;
   struct node *right;
};
typedef struct node *NODEPTR;

NODEPTR create_node(int num)
{
     NODEPTR temp = (NODEPTR)malloc(sizeof(struct node));
     temp->val = num;
     temp->left = NULL;
     temp->right = NULL;
     return temp;
} 

NODEPTR insert_node(NODEPTR nd,NODEPTR newnode)
{
    if(nd==NULL)
       return newnode;/* newnode becomes root of tree*/
    if(newnode->val > nd->val)
        nd->right = insert_node(nd->right,newnode);
    else if(newnode->val <  nd->val)
        nd->left = insert_node(nd->left,newnode); 
    return nd;   
}

void in_order(NODEPTR nd)
{
   if(nd!=NULL)
    {
        in_order(nd->left);
        printf("%d---",nd->val);
        in_order(nd->right);
     }
}
NODEPTR lowest_common_ancestor(NODEPTR root, int num1,int num2)
{
   NODEPTR temp = root;
   while(temp!=NULL)
   {
        if(num1>temp->val && num2>temp->val ) 
              temp = temp->right; 
        else if(num1<temp->val && num2<temp->val)
              temp= temp->left;
        else
              break; 
    }
    return temp;  
} 


int main()
{
       NODEPTR root=NULL,delnode; 
       int n;
       do
       {
           NODEPTR newnode;
           printf("Enter value of node(-1 to exit):");
           scanf("%d",&n);
           if(n!=-1)
            {  
               newnode = create_node(n);
               root = insert_node(root,newnode);
             }
       } while (n!=-1);
       
       printf("\nInorder traversal\n");
       in_order(root);
      
       while(1)
       {
          NODEPTR snode;
          int num1,num2;
          printf("Enter two values num1 and num2:");
          scanf("%d %d",&num1,&num2);
          snode = lowest_common_ancestor(root,num1,num2);
          if(snode==NULL)
             printf("Value not found");
          else 
             printf("ancestor is %d\n",snode->val);
       }
       return 0;
}

Comments

Popular posts from this blog

Delete a node from doubly linked list

Deletion operation in DLL is simpler when compared to SLL. Because we don't have to go in search of previous node of to-be-deleted node.  Here is how you delete a node Link previous node of node of to-be-deleted to next node. Link next node of node of to-be-deleted to previous node. Free the memory of node of to-be-deleted Simple, isn't it. The code can go like this. prevnode = delnode->prev; nextnode = delnode->next; prevnode->next = nextnode; nextnode->prev = prevnode; free(delnode); And that is it. The node delnode is deleted. But we should always consider boundary conditions. What happens if we are trying to delete the first node or last node? If first node is to be deleted, its previous node is NULL. Hence step 3 should not be used.  And also, once head is deleted, nextnode becomes head . Similarly if last node is to be deleted, nextnode is NULL. Hence step 4 is as strict NO NO. And we should set prevnode to tail. After we put these things together, we have...

Function to sort an array using bubble sort

Quick and dirty way of sorting an array is bubble sort. It is very easy to write and follow. But please keep in mind that it is not at all effecient. #include<iostream> using std::cin; using std::cout; void readArray(int arr[],int sz); void printArray(int arr[],int sz); void sortArray(int arr[],int sz); void swap(int &a,int &b); int main() {    int sz;    cout<<"Size of the array=";    cin>>sz;    int arr[sz];    readArray(arr,sz);     sortArray(arr,sz);   cout<<"Sorted array is ";   printArray(arr,sz); } void readArray(int arr[],int sz) {  for(int i=0;i<sz;i++)    {       cout<<"arr["<<i<<"]=";       cin>>arr[i];   } } void printArray(int arr[],int sz) {  for(int i=0;i<sz;i++)    {       cout<<"arr["<<i<<"]=";    ...

Merge two binary search trees

How do you merge two binary search trees? I googled about the solutions. Most solutions told me to convert both trees into linked lists. Merge the lists. Then create a tree from the elements of the list. But why lists? Why can't we store the elements in an array? Because if the data of the tree is larger - not just integer keys, array manipulation becomes difficult. But again, we need not convert both the trees into lists. We can convert one tree into list - a doubly linked list. Then insert the elements of this list into the other tree. I tried this approach. To convert a tree into a sorted doubly linked list Create a doubly linked list. Let the prev and next links of nodes in this list be called left and right respectively. This way we can directly use the binary tree nodes in the list. Use a static variable previousnode  call the function recursively for left child of current node. link current node to the previousnode set next pointer of previousnode to curre...