Skip to main content

Queue data structure

Queue is a linear data structure to which values are added and removed using FIFO method - first in first out. That is to say, the value which is added first, will be removed first from the queue. Exactly like the behavior of a real life queue.

The other related data structure is stack, from which elements are added and removed using LIFO method - last in first out.

Terminology





An element is always added to the rear end of the queue. This operation is called enqueue

An element is added from the front end of the queue. The operation of removing an element is called dequeue operation.


Implementation of queue

You can implement a queue using an array or a linked list. Array poses the problem that it is limited by its size. But by making the array as circular, queue can be implemented. Here when the array index reaches maximum value, queue insertion happens at the beginning of the array.

But implementation of a queue with linked list is not having such limitations. If you just add one more pointer for front end of the queue, all operations can be implemented with O(1) complexity.

Let us look at the algorithm for queue using linked list

  • Enqueue operation
    • create a new node
    • if rear is NULL, rear = front = newnode
    • else link rear node to newnode
    • set rear as newnode
  •  Dequeue operation
    • if queue is empty return error code
    • set temp to front
    • set front to next node of front
    • free the memory allocated to front node
    • return the value of temp
  • IsEmpty
    •  if front = null and rear = null return true
Do not forget the initialize the queue by setting front and rear equal to NULL. You don't want to get segmentation fault.

Enqueue operation


NODEPTR create_node(int n)
{
NODEPTR newnode = malloc(sizeof(struct node));
newnode->num = n;
newnode->next = NULL;
return newnode;
}

void enqueue(QUEUE *q1,int n)
{
NODEPTR temp = create_node(n);
if(is_empty(q1))
{
q1->rear = q1->front = temp;
}
else{
q1->rear->next = temp;
q1->rear = temp;
}
}

Next let us look at dequeue function


int is_empty(QUEUE *q1)
{
return (q1->front==NULL && q1->rear==NULL);
}
int dequeue(QUEUE *q1)
{
if(is_empty(q1))
return -1;

NODEPTR temp = q1->front;
int m = temp->num;
q1->front = q1->front->next;
free(temp);
if(q1->front==NULL)
q1->rear = NULL;
return m;
}

I have added an additional line in dequeue function, if the q1->front = NULL then even q1->rear = NULL, because when all the nodes are removed from the queue, both pointers must be NULL.

And here is the complete program.

#include<stdio.h>
#include<stdlib.h>
struct node
{
int num;
struct node *next;
};

typedef struct node *NODEPTR;

struct queue
{
NODEPTR front,rear;
};

typedef struct queue QUEUE;


NODEPTR create_node(int n)
{
NODEPTR newnode = malloc(sizeof(struct node));
newnode->num = n;
newnode->next = NULL;
return newnode;
}
int is_empty(QUEUE *q1)
{
return (q1->front==NULL && q1->rear==NULL);
}
void enqueue(QUEUE *q1,int n)
{
NODEPTR temp = create_node(n);
if(is_empty(q1))
{
q1->rear = q1->front = temp;
}
else{
q1->rear->next = temp;
q1->rear = temp;
}
}

int dequeue(QUEUE *q1)
{
if(is_empty(q1))
return -1;

NODEPTR temp = q1->front;
int m = temp->num;
q1->front = q1->front->next;
free(temp);
if(q1->front==NULL)
q1->rear = NULL;
return m;
}

void display(QUEUE q1)
{
NODEPTR node=q1.front;
printf("\nThe list is \n");
while(node !=NULL)
{
printf("%d----",node->num);
node = node->next;
}
}

int main()
{
QUEUE q1;
/*initialize queue*/
q1.front = q1.rear = NULL;

while(1)
{
int ans;
printf("Enter 1 - Add a node 2 - remove a node 3 - quit\n");
scanf("%d",&ans);
if (ans==1)
{
int n;
printf("Node to enqueued:");
scanf("%d",&n);
enqueue(&q1,n);
display(q1);
}else if (ans==2)
{
int n;
n = dequeue(&q1);
if(n==-1)
printf("THe queue is empty");
else
printf("The value dequed is %d\n",n);
display(q1);
}
else
break;
}
return 0;
}

Comments

Popular posts from this blog

In order traversal of nodes in the range x to y

Question : Write a function for in-order traversal of nodes in the range x to y from a binary search tree. This is quite a simple function. As a first solution we can just traverse our binary search tree in inorder and display only the nodes which are in the range x to y. But if the current node has a value less than x, do we have to traverse its left subtree? No. Because all the nodes in left subtree will be smaller than x. Similarly if the current node has a key value more than y, we need not visit its right subtree. Now we are ready to write our algorithm.     if nd is NOT NULL  if nd->val >=x then visit all the nodes of left subtree of nd recursively display nd->val if nd->val <y then visit all the nodes of right subtree of nd recursively  That's all. We have our function ready. void in_order_middle (NODEPTR nd, int x, int y) { if (nd) { if (nd -> val >= x) in_order_middle(nd...

Josephus problem

Question: Write a function to delete every k th node from circular linked list until only one node is left. This has a story associated with it. Flavius Josephus was Jewish Historian from 1st century. He and 40 other soldiers were trapped in a cave by Romans. They decided to kill themselves rather than surrendering to Romans. Their method was like this. All the soldiers will stand in a circle and every k th soldier will be shot dead. Josephus said to have calculated the starting point so that he would remain alive. So we have similar problem at hand. We delete every kth node in a circular list. Eventually only one node will be left. e.g. Let us say this is our list And we are deleting every third node.  We will delete 30. Then we delete 60. Next we delete 10. Next it will be 50. Next to be deleted is 20. Next 80. This continues. Implementation   We can count k-1 nodes and delete next node. This can be repeated in  a loop. What must be the termina...

Delete a node from doubly linked list

Deletion operation in DLL is simpler when compared to SLL. Because we don't have to go in search of previous node of to-be-deleted node.  Here is how you delete a node Link previous node of node of to-be-deleted to next node. Link next node of node of to-be-deleted to previous node. Free the memory of node of to-be-deleted Simple, isn't it. The code can go like this. prevnode = delnode->prev; nextnode = delnode->next; prevnode->next = nextnode; nextnode->prev = prevnode; free(delnode); And that is it. The node delnode is deleted. But we should always consider boundary conditions. What happens if we are trying to delete the first node or last node? If first node is to be deleted, its previous node is NULL. Hence step 3 should not be used.  And also, once head is deleted, nextnode becomes head . Similarly if last node is to be deleted, nextnode is NULL. Hence step 4 is as strict NO NO. And we should set prevnode to tail. After we put these things together, we have...