In order traversal of nodes in the range x to y

Question : Write a function for in-order traversal of nodes in the range x to y from a binary search tree.

This is quite a simple function. As a first solution we can just traverse our binary search tree in inorder and display only the nodes which are in the range x to y.

But if the current node has a value less than x, do we have to traverse its left subtree? No. Because all the nodes in left subtree will be smaller than x.

Similarly if the current node has a key value more than y, we need not visit its right subtree.

Now we are ready to write our algorithm.

if nd is NOT NULL

if nd->val >=x then

visit all the nodes of left subtree of nd recursively

display nd->val
if nd->val <y then

visit all the nodes of right subtree of nd recursively

That's all. We have our function ready.

void in_order_middle(NODEPTR nd,int x, int y)
{
    if(nd)
    { 
        if(nd->val >=x)
             in_order_middle(nd->left,x,y);
 if(nd->val>=x && nd->val<=y)
     printf("%d  ",nd->val);
 if(nd->val <=y)
           in_order_middle(nd->right,x,y); 
    }
}

Comments

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