Skip to main content

Stack implementation using linked list

A stack data structure is a versatile data structure which is useful whenever we want output to be reverse of input, or we want a LIFO - last in first out behavior
Image from Wikipedia
.

A function call in most languages employs a stack. The parameters and local variables are pushed to call stack. And a return statement pops out most recent call stack.

Similarly when we want to check if an expression has balanced brackets, we can use a stack to store brackets.

Top of stack:

 Unlike a linked list where elements can be added to the end of list or beginning of a list, values are always added to the top of the stack. Just like a plate is added to the top of a stack of plates.

And a value is always removed from top of the stack - similar to a stack of plates again.

A stack abstract data type should define three functions
  1. push - push function inserts a value at the top of stack 
  2. pop - pop function removes a value from top of stack
  3. isempty - isempty function checks if the stack is empty
  4. peek or top - this gives the value at the top of stack
Implementation

A stack can be implemented using an array or a linked list. In both these implementations, all of the 4 functions will have O(1) time complexity. In array implementation top will be the index in array.

Let us look at linked list implementation of a stack

Linked List implementation:

In linked list implementation of stack, top of stack can be a node pointer just like head. And to push a value to stack, a node should be added to beginning of list.


NODEPTR push(NODEPTR top,NODEPTR newnode)
{
newnode->next = top;
top = newnode;
return top;
}



To pop a value from stack, a node must be deleted from beginning of linked list.


int pop(NODEPTR *topPtr)
{
if(isempty(*topPtr))
return ERROR;
int num = (*topPtr)->n;
NODEPTR temp = *topPtr;
*topPtr = (*topPtr)->next;
free(temp);
return num;
}

And checking whether the stack is empty is just checking if top is NULL.

int isempty(NODEPTR top)
{
return top==NULL;
}

 Here is the driver  program.


#include<stdio.h>  
#include<stdlib.h>
#define ERROR -1000
struct node
{
int n;
struct node *next;
};
typedef struct node * NODEPTR;

NODEPTR create_node(int value)
{
NODEPTR temp = (NODEPTR) malloc(sizeof(struct node));
temp->next = NULL;
temp->n = value;
return temp;
}
NODEPTR push(NODEPTR top,NODEPTR newnode)
{
newnode->next = top;
top = newnode;
return top;
}
int isempty(NODEPTR top)
{
return top==NULL;
}
int pop(NODEPTR *topPtr)
{
if(isempty(*topPtr))
return ERROR;
int num = (*topPtr)->n;
NODEPTR temp = *topPtr;
*topPtr = (*topPtr)->next;
free(temp);
return num;
}

int main()
{
NODEPTR top = NULL;
NODEPTR nd;

while(1)
{
int option,value;
printf("Enter 1- push 2- pop 3 - exit");
scanf("%d",&option);
if(option==3)
break;
switch(option)
{
case 1: printf("new value to push=");
scanf("%d",&value);
nd = create_node(value);
top = push(top,nd);
break;
case 2: value = pop(&top);
if(value==ERROR)
printf("Stack empty\n");
else
printf("Value popped is %d\n",value);
break;
}
}
}


Comments

Popular posts from this blog

Linked list in C++

A linked list is a versatile data structure. In this structure, values are linked to one another with the help of addresses. I have written in an earlier post about how to create a linked list in C.  C++ has a library - standard template library which has list, stack, queue etc. data structures. But if you were to implement these data structures yourself in C++, how will you implement? If you just use new, delete, cout and cin, and then claim it is your c++ program, you are not conforming to OOPS concept. Remember you have to "keep it together". Keep all the functions and variables together - in a class. You have to have class called linked list in which there are methods - append, delete, display, insert, find, find_last. And there will also be a data - head. Defining node We need a structure for all these nodes. A struct can be used for this purpose, just like C. struct node { int val; struct node * next; }; Next we need to define our class. W

Swap nodes of a linked list

Qn: Write a function to swap the adjacent nodes of a singly linked list.i.e. If the list has nodes as 1,2,3,4,5,6,7,8, after swapping, the list should be 2,1,4,3,6,5,8,7 Image from: https://tekmarathon.com Though the question looks simple enough, it is tricky because you don't just swap the pointers. You need to take care of links as well. So let us try to understand how to go about it. Take two adjacent nodes p1 and p2 Let prevnode be previous node of p1 Now link prevnode to p2 Link p2 to p1 Link p1 to next node of p2 So the code will be prevnode -> next = p2; p1 -> next = p2 -> next; p2 -> next = p1; But what about the start node or head? head node does not have previous node If we swap head with second node, modified head should be sent back to caller  To take care of swapping first and second nodes, we can write p1 = head; p2 = head -> next; p1 -> next = p2 -> next; p2 -> next = p1; head = p2;  Now we are read

Binary tree deletion - non-recursive

In the previous post we have seen how to delete a node of a binary search tree using recursion. Today we will see how to delete a node of BST using a non-recursive function. Let us revisit the 3 scenarios here Deleting a node with no children just link the parent to NULL Deleting a node with one child link the parent to  non-null child of node to be deleted Deleting a node with both children select the successor of node to be deleted copy successor's value into this node delete the successor In order to start, we need a function to search for a node in binary search tree. Did you know that searching in  a BST is very fast, and is of the order O(logn). To search Start with root Repeat until value is found or node is NULL If the search value is greater than node branch to right If the search value is lesser than node branch to left.  Here is the function NODEPTR find_node (NODEPTR root,NODEPTR * parent, int delval) { NODEPTR nd = root; NODEPTR pa = root; if (root -> v